The figure shows a closed container of uniform cross-section. The cross section consists of a square ABCD and a quadrant CED of a circle, centre D. Given that AB=7cm, AD=7cm and BH=CG=EF=AI=20cm, calculate
- The area of the cross section ADECB
- The volume of the container
- The surface area BCEFGH
[Take \(𝜋=\frac{22}{7}\)]